This isn't a single JSON object. You have an array of JSON objects. You need to loop over array first and then access each object. ... <看更多>

JSON defines only two data structures: objects and arrays. An object is a set of name-value pairs, and an array is a list of values. JSON defines seven value ... ... <看更多>

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You need to first unnest the array elements, and then aggregate back each value: select id, (select jsonb_agg(t -> 'a') from ... ... <看更多>

I want to store multiple images (with different attributes) per tile-type and find the correct json object that matches a key. like: Type ... ... <看更多>